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Q: Why does the reference variable below print the original value of object? I was wondering what is the point of printing the original object, i thought after getting the “Hi” from the original object, the reference to the original object should be discarded. //Java code public class javaprojectexchange { public static void main(String args[]){ String a=”Hi”; String b=””; JavaBean jb=new JavaBean(a); System.out.println(jb); String object=jb.getA(); System.out.println(object); } } class JavaBean{ String a; public String getA(){ return a; } } A: By default, the reference to the object is stored in a local variable, called this. Usually, the this variable is automatically created when the constructor is called. When the constructor returns, the object itself will no longer exist. There is no direct way to store the reference to the object in an ical. (You can have a local variable that is an instance of an object, but that variable won’t be a reference anymore.) You have an object and a variable that reference the same object, so the variable still has a reference to the object. If you reassign a to be null, the reference will be lost, but your variable will still have a reference to the object. (That’s why the object keeps printing.) The following line looks a bit weird, since a and object aren’t the same thing. String object=jb.getA(); You can think of a as a “pointer” to the object in memory. All this means that object and a are not the same thing, so reassigning a doesn’t mean that object is lost and is unreachable. The original object still exists and is accessible. Dear Mr. President, You were appointed to the office of President of the United States on the 28th of January 2017. Your position as President was not created to protect the interests of the man who was elected, but rather to protect the people of the United States of America.
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