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MEXICO CITY, MEXICO – The Mexican Red Cross Society (Cruz Roja Mexicana) announced today that it has assigned almost 600 staff to be on standby in and around Michoacán, Guerrero and Jalisco during Tropical Storm Manuel.
Members of the Red Cross have been assigned to centres set up to receive storm victims and equip them with personal hygiene kits. The Red Cross Mexicana is also training and equipping 70 local first responders, sent from areas with extreme weather conditions that have been hit by Tropical Storm Manuel.Q:
Recursively call function based on argument
I am trying to define a function that makes another function call itself on an argument. For example,
myfunc(0)
>>> 1
myfunc(1)
>>> 2
myfunc(2)
>>> 3
I don’t need any additional arguments, just the optional one. How should I do this?
A:
You can solve this using recursion. Here’s a simple example:
def myfunc(i):
if i == 0:
return 1
else:
return myfunc(i – 1) + myfunc(i – 1)
print myfunc(5) # => 24
Note: your stated example has syntax errors, and since your questions concerns recursive functions, I’d expect to see a few more attempts to solve the problem that don’t work.
Q:
How does the definition of $\displaystyle\int_{0}^{0}\ln{\left|\frac{x}{a}\right|} dx$ change as $a \to 0$?
I am trying to find the derivative of the following function:
$$G(a) = \int_{0}^{0}\ln{\left|\frac{x}{a}\right|} dx.$$
The $x$-argument of the logarith
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